Giancoli's Physics: Principles with Applications, 6th Edition
5
Circular Motion; Gravitation
Change chapter5-1 to 5-3: Uniform Circular Motion; Highway Curves
5-4: Nonuniform Circular Motion
5-6 and 5-7: Law of Universal Gravitation
5-8: Satellites; Weightlessness
5-9: Kepler's Laws
Problem 22
A
down along the ramp
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COMMENTS
By Mr. Dychko on Sat, 11/6/2010 - 1:39 AM
Thanks for spotting that sroman. It's now fixed. =)
By sroman on Fri, 11/5/2010 - 5:12 AM
The video ends without solving the problem :(
By wojiyabei on Thu, 5/5/2011 - 1:51 PM
i thought there is a short cart to do it
Ffrx=cos(12)Fr-sin12Fr
therefore we can calculate the fraction directly
By Mr. Dychko on Mon, 10/8/2012 - 3:39 PM
Thanks okstate2015 for your sharp eye. In the very last step I made a mistake changing to scientific notation and should have written times 10^3 as you say. I've added the video to my "update" list.
By okstate2015 on Mon, 10/8/2012 - 2:32 PM
Correct answer is 9.8 x 10^3 N rather than 10^2 N.
By Dbx86x on Fri, 10/19/2012 - 9:41 PM
How is 1200(26.39^2)/67=10,714 N?
By Mr. Dychko on Sun, 12/2/2012 - 5:18 AM
This video has been updated!
By JayMatthews on Wed, 6/5/2013 - 12:32 AM
I think I better look at this over and over again to really get it.
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