WEBVTT

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This is Giancoli Answers
with Mr. Dychko.

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So this question involves a lot of algebra
so fasten your seat belt as we

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wend our way through all that stuff there
but hopefully I'll make it make sense.

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So we have the specific gravity of the body,

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it's the body's density divided by

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density of water, that's the definition
of specific gravity;

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so we take that total mass of the body
and divide by

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the total volume to get the density of
the body and then divide that by

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density of water so this is specific
gravity here as well

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and we are told that that
equals the letter <i>X</i>.

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So we need some way to get this
little <i>f</i> involved here because

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our final answer has to be to show

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that you know, <i>f</i> times a 100
which will be

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percent body mass equals some stuff
that we are showing there—

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495 over <i>X</i> minus 450.

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So this <i>f</i> has to be involved here somehow

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so we are gonna make it appear
within this volume part.

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So we know volume is the volume of
the fat in the body plus

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the volume of the fat-free
part of the body

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and the volume of the body consisting
of fat is the mass that is fat divided by

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the density of fat

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plus the mass that is fat free divided by
the density that is fat free.

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Substituting you know, you have
the density definition is

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mass over volume and you can
solve for volume by

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multiplying both sides by

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<i>V</i> and dividing both sides by <i>ρ</i>
and you end up with

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<i>V</i> on the left equals mass
divided by density.

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So that's what I'm substituting here:

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mass divided by density in place of volume.

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And then further we can say that <i>m f</i>
divided by <i>m</i> is <i>f</i>

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because <i>f</i> represents the fraction of
the total mass which is fat

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so the mass that is fat divided by
total mass is <i>f</i>

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and we can rearrange this by

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multiplying both sides by total mass
and we get

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mass of the body which is fat is this
fraction that is fat

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times the total mass and we are gonna
substitute that in

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for <i>m f</i> here—that's what
I did in that line—

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and then mass that is fat-free has to be

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1 minus the fraction that contains fat

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times the total mass.

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I guess to explain that I would say

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<i>m f</i> divided by <i>m</i> plus <i>m ff</i>

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or <i>m</i> has to equal 1 because

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this makes up a 100 percent of all
mass in the body so

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<i>m ff</i> has to equal 1 minus <i>m f</i> over <i>m</i>

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all multiplied by <i>m</i>

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but this thing right in here is <i>f</i>

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and so we have 1 minus <i>f</i> times <i>m</i>
is <i>m ff</i> as shown here.

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Okay.

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So plug each of these things

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into these numerator's in this
volume expression

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and we have the total volume

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that consist of fat plus volume
that is fat-free is

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<i>f</i> times <i>m</i> over density of fat plus

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1 minus <i>f</i> times <i>m</i> over the density of
the fat-free material

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and then plugging that all in for
total volume in this expression

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I guess this part of it anyway

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plugging in for <i>V</i> there in red

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I have total mass divided by
density of water

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times this whole business for
the total volume

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equals <i>x</i> and now... (what do I say here?)

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We want to solve for <i>f</i> which is
a nasty thing because

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it's buried within this denominator

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and well, first of all, let's say

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multiply both sides by 1 over <i>X</i>

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and then that gets rid of the <i>X</i>
on the right side

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and leaves us with an <i>X</i> on the left side
so we have <i>m</i> over <i>X</i>

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and then multiply both sides also
by this denominator

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so that on the left side, it disappears

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and on the right side, it's the only thing
that's there because

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<i>X</i> over <i>X</i> makes 1 and then we are left
only with 1 times this denominator

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and then switch the sides around too

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so that we have this unknown stuff on the left.

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So we have <i>m</i> over <i>X</i> equals
this whole denominator

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and then I expanded the denominator too

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so I multiplied this <i>ρ w</i> into
each of the terms

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so we have <i>ρ w</i> times <i>f</i> times <i>m</i>
over <i>ρ f</i>

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plus 1 minus <i>f</i> times <i>ρ w</i> times <i>m</i>
over <i>ρ ff</i> equals <i>m</i> over <i>X</i>.

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That might be the hardest algebra step
in this sequence

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because I kinda did a couple things at once
there but hopefully that made sense.

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Some teachers refer to what I did here
as cross-multiplying;

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you can multiply... even that's not
a very good way to explain it

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never mind the cross-multiplying.

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So.. there. Let's go to the next line!

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Let's expand this stuff and multiply

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both these terms in this bracket by
<i>ρ w</i> times <i>m</i>

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so we have 1 times <i>ρ w</i> times <i>m</i>
over <i>ρ ff</i>

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and by the way, the <i>m</i>'s canceled...
(okay there we go) so there's no <i>m</i>

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it's a common factor on both sides so
we can divide both sides by it

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and it's gone

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so we have <i>ρ w</i> times 1 over <i>ρ ff</i>

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so that's just <i>ρ w</i> over <i>ρ ff</i>

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minus <i>f</i> times <i>ρ w</i> over <i>ρ ff</i>

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and I'm writing them as
separate terms here

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and never mind keeping them as one
fraction, make them two fractions

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because we wanna collect the two terms
that contain the <i>f</i>.

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So we do that in the next line and
we have <i>f</i> times <i>ρ w</i>

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being a common factor for
both these terms

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and multiplied by, you know, what ends up
being a 1 here over <i>ρ f</i>

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minus 1 over <i>ρ ff</i>

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and then this term got moved

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to the right hand side by subtracting it
from both sides so it's <i>ρ w</i> over <i>ρ ff</i>.

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And then write this as a single fraction

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so common denominator makes this
<i>ρ ff</i> over <i>ρ ff</i>,

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multiply this by <i>ρ f</i> over <i>ρ f</i>

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and you have <i>ρ ff</i> minus <i>ρ f</i> over
<i>ρ f</i> times <i>ρ ff</i>.

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That's all I did in that line

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and then multiply both sides by <i>ρ f</i>

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times <i>ρ ff</i> so we have <i>ρ f</i> times
<i>ρ ff</i> over <i>X</i>

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and then it's just the <i>ρ f</i> when you
multiply this term by that

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denominator because the <i>ρ ff</i>'s cancel

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and so you are just left with <i>ρ f</i>

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and then we are also dividing both sides by

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<i>ρ w</i> times bracket <i>ρ ff</i> minus <i>ρ f</i>

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and so that's where this comes from
that's just, you know, copied there

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but whereas over here,

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it's missing the <i>ρ w</i> because
it cancels with this one

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and so it's just <i>ρ ff</i> minus <i>ρ f</i>.

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And finally, we plug in some numbers

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and it all handily works out to
what we needed to.

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So we have density of fat is 0.90 grams
per centimeter cubed

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times 1.10 grams per centimeter cubed
for the fat-free material

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divided by <i>X</i> times 1 gram per centimeter
cubed—density of water—

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times a difference between those
fat free and the fat density

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minus 0.90 divided by 1.10 minus 0.90

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and you end up with 4.95 over <i>X</i> minus 4.5

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that's the fraction which is fat

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and if we want the percent, we have to
multiply both sides by 100

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and so this gives a percent
which is body fat

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which will be 495 over <i>X</i> minus 450.