Giancoli 7th Edition textbook cover
Giancoli's Physics: Principles with Applications, 6th Edition
6
Work and Energy
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6-1: Work, Constant Force
6-3: Kinetic Energy; Work-Energy Principle
6-4 and 6-5: Potential Energy
6-6 and 6-7: Conservatino of Mechanical Energy
6-8 and 6-9: Law of Conservation of Energy
6-10: Power

Problem 1
A
Wg=7.27×103JW_g=7.27 \times 10^3 J
Giancoli 6th Edition, Chapter 6, Problem 1 solution video poster
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VIDEO TRANSCRIPT

This pile driver can do as much work as the work done on it by gravity. So the work done on this pile driver by gravity is equal to the force of gravity which is 'mg' and then we’ll multiply that by the distance that it falls. First let’s figure out the force. That’s 265 kilograms times 9.8 newtons per kilogram and that is 2,597 newtons. And the distance over which this force is acting is 2.8 meters because that’s how far it falls. So work done by gravity is the force of gravity times the displacement. These are parallel so we don’t have to worry about any directions at all here. So we have that force times 2.8 meters and we get the work done, ### times ## to the # joules.

COMMENTS
By 100alexis on Thu, 2/3/2011 - 7:11 AM

CAN I SEE?

By Mr. Dychko on Thu, 2/3/2011 - 5:18 PM

Definitely! You can subscribe by clicking the following link: http://www.checkmarkmedia.com/chapter-6-energy

By 100alexis on Sat, 2/5/2011 - 3:32 AM

can i see the solution without payment? please!!

By schafdaddy on Tue, 11/13/2012 - 5:44 AM

Awesome helped sooooo much

By estherjlee93 on Fri, 3/1/2013 - 6:08 AM

If there are no videos for General Problems, is there any online solution key that shows me how to solve them?

Thank you!

By tasperrin on Wed, 5/14/2014 - 2:17 AM

i love yah

By Mr. Dychko on Wed, 5/14/2014 - 5:03 PM

Wow, so many nice vibes coming from Australia. You guys are so friendly! :)

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