Giancoli Solutions on Video

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  • 1,930 video solutions for all regular problems in Giancoli's 7th Edition and 1,681 solutions for most regular problems in the 6th Edition.
  • Final answer provided in text form for quick reference above each video, and formatted nicely as an equation, like $E=mc^2$. This is useful if you are in the library or have a slow internet connection.

  • Pen colors make the step-by-step solutions clear. Red is used to illustrate algebra steps, and to substitute numeric values in the final step of a solution. When a solution switches to a new train of thought a different pen color emphasizes the switch, so that solutions are very methodical and organized.
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Sample solution

Giancoli 7th Edition, Chapter 4, Problem 62


Recent questions and answers

Thank you very much @holland016, I've updated the quick answer.

your answer for b is incorrect it should be 8x10*-11

@micisner, my pleasure, and it's great there is an easy fix!

Hi swedesanddanes, I'm guessing that the confusing part is the $x_{2i}$ in $x_2 = x_{2i} + v_2 t$, correct? For most questions it's typically enough to say something like $x_2 = v_2 t$, but the reason this is usually OK is that normally you choose the initial position to be zero, in which case $x_2 = x_{2i} + v_2 t$ would be the same as $x_2 = v_2 t$ since $x_{2i} = 0$ when the initial position is zero. This question, however, is not one of your usual questions. The second train begins at an initial position of $8.5 \textrm{ m}$, in which case $x_{2i} = 8.5 \textrm{ m}$, so this initial position term is needed in the position formula.

Just to check your understanding, notice how we could have instead chosen $x_{2i} = 0$ after all, but then the initial position of train 1 would need to be $x_{1i} = -8.5 \textrm{ m}$ (assuming positive is directed toward the right).

Hope this helps,
Mr. Dychko

You were totally right! My calculator was in radian. Thank you so much for your help.