Giancoli Solutions on Video

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The videos were extremely helpful. You can play them over and over and pause them to review. The narrator explained the steps beautifully and provided details on performing the algebraic manipulations. Different colored pens made it easy to differentiate steps. My Physics teacher often moved through the material very fast in class. The videos allowed me to review areas I found difficult as many times as I needed. Giancoli Answers was a wonderful learning tool for understanding Physics.


  • 1,930 video solutions for all regular problems in Giancoli's 7th Edition and 1,681 solutions for most regular problems in the 6th Edition.
  • Final answer provided in text form for quick reference above each video, and formatted nicely as an equation, like $E=mc^2$. This is useful if you are in the library or have a slow internet connection.

  • Pen colors make the step-by-step solutions clear. Red is used to illustrate algebra steps, and to substitute numeric values in the final step of a solution. When a solution switches to a new train of thought a different pen color emphasizes the switch, so that solutions are very methodical and organized.
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Sample solution

Giancoli 7th Edition, Chapter 5, Problem 12


Recent questions and answers

Giancoli 7th Edition, Chapter 6, Problem 52

By lcbishop on Mon, 10/24/2016 - 11:35

Can you give a brief explanation of what you mean by "energy goes into heat"? Is it transformed into heat? Thanks.

Giancoli 7th Edition, Chapter 6, Problem 31

By jessicasingh001 on Sun, 10/23/2016 - 18:46

Does anyone know why the 8 degree incline is ignored?

Giancoli 7th Edition, Chapter 7, Problem 28

By gillander97 on Sun, 10/23/2016 - 15:26

no sound ;-(

Giancoli 7th Edition, Chapter 4, Problem 66

By tongmeng.zhang on Sat, 10/15/2016 - 11:43

Is there anyway the solutions can be laid out onto one sheet so there isn't much scrolling? The calculations are nice and detailed but I lose my train of thought every time the scrolling happens. Makes it hard to follow the solutions -Alice Zhang

By Mr. Dychko on Sun, 10/16/2016 - 03:53

Hi tongmeng.zhang, yes I can see what you mean, especially on a 10min video. The video is a screen capture of my computer screen. I wonder if in the future I should change the orientation of the screen to be in "portrait" mode rather than "landscape"? It would sacrifice some width, but would keep more of the work on the screen at once. Unfortunately for the videos that are already made it would be difficult to change things. I could "zoom out", but then it would be too small to read. Thanks for the feedback though, since I'll try using "portrait" mode on future videos.

All the best,
Mr. Dychko

Giancoli 7th Edition, Chapter 3, Problem 33

By lcbishop on Thu, 10/13/2016 - 21:31

In the beginning when we solved for the Vx Initial and got 2.3077 why did we also use that in the magnitude calculation in the end? We solved for a final velocity of y, but we reused the velocity of x, could you please explain. Thanks.

By Mr. Dychko on Sun, 10/16/2016 - 03:59

Hi Icbishop, thanks for the question. Just to be clear, we're talking about part a), right? In part a) we solved for the resultant velocity, which is to say we solved for the vector sum of the x and y components. The answer for part a) is not the final velocity of y, but rather the final resultant velocity, which is normally just referred to as the velocity, but I'm including the word resultant to answer your question by explaining that the velocity is arrived at by using the pythagorean theorem to get it's magnitude by taking the square root of the sum of the squares of the x and y components of the velocity, and using trigonometry to get the direction.

Hope that helps,
Mr. Dychko

Giancoli 7th Edition, Chapter 2, Problem 49

By idan on Thu, 10/13/2016 - 17:13

Do you think it's acceptable to use a graphing calculator to find the zeros of these functions? We're studying physics, not math.

By Mr. Dychko on Sun, 10/16/2016 - 03:47

Hi idan, I think it's a matter of personal opinion. Yes, using a graphing calculator is fine, but an "analytical solution" (ie. with algebra) can be useful too. The advantage of an algebra solution is that you can learn from an algebraic solution, and more generally characterize the behaviour of a system. Sorry to be so abstract, but we're talking about solutions in general, so it's difficult to be concrete. But consider the solution to problem 32 in chapter 4: $a = \dfrac{gm_B}{m_A + m_b}\textrm{ , } F_T = \dfrac{gm_Am_B}{m_A + m_B}$. That's an analytical solution, and it wouldn't be possible to use a graphing calculator since there are no numbers given in the problem. By looking at that analytical solution you can say things like "the acceleration decreases as $m_A$ increases", or "the tension force increases in proportion to both $m_A$ or $m_B$". Being able to create an analytical solution is important, so I guess my answer to your question is: yes, it's OK to use a graphing calculator, but make sure you could create an analytical solution if you had to, since that's your only option for problems with no numbers. It's like driving a race car: it's OK to drive it fast if you're a skilled driver, but not OK to drive fast if you're doing so just because you're unable to drive slow.

Thanks for the good question.
All the best,
Mr. Dychko

Giancoli 7th Edition, Chapter 2, Problem 39

By lcbishop on Sat, 10/08/2016 - 17:17

If for instance we considered down not to be positive and ended up with a negative. Does this essentially make the answer wrong?

By Mr. Dychko on Sun, 10/09/2016 - 13:00

Hi Icbishop, thanks for the question. It's fine to choose the coordinate system you prefer (such as up as positive, which is conventional), and this will result in a correct calculation regardless of which choice you made, but you need to be aware of what the question is asking for. In this case the question is asking for the height of the cliff. Heights are always positive. They're a magnitude. This means that regardless of whether your calculation results in a positive or negative, you would give a positive as your final answer. The calculation gives you the displacement of the stone, but "displacement of the stone" is not what the question is asking for. The cliff height is the magnitude of the stone's displacement, which is to say the "absolute value", which are two fancy ways of saying "make it positive".

Hope that helps,
Mr. Dychko

Giancoli 7th Edition, Chapter 18, Problem 3

By daniel.weiss1 on Fri, 09/30/2016 - 11:02

Great video, small note: I think you mistakenly have coulombs in your answer above the video instead of amps.

By Mr. Dychko on Sun, 10/09/2016 - 13:01

Thanks daniel.weiss1! I just fixed it.

All the best,
Mr. Dychko