These videos are 40 times more valuable than lecture, the text book, and so much cheeper and efficient than a private tutor.

# Giancoli Solutions on Video

Learn physics easily with guided practice.

Achieve your
goals with top grades.

## Free Trial

Get instant access to 3,500+ 7th and 6th Edition solutions.## Trusted by more than 1,900 students

Just wanted to drop a note and thank you for this amazing service! And thank you for working hard on this, it is greatly appreciated :D

The videos were extremely helpful. You can play them over and over and pause them to review. The narrator explained the steps beautifully and provided details on performing the algebraic manipulations. Different colored pens made it easy to differentiate steps. My Physics teacher often moved through the material very fast in class. The videos allowed me to review areas I found difficult as many times as I needed. Giancoli Answers was a wonderful learning tool for understanding Physics.

This is a wonderful service. He goes over all of the problems of each chapter and gives both the answer in a quick text form (good if you are on your cell in the library etc) AND has a video which explains the entire problem if you want a detailed explanation. It's like having a tutor, which is a huge help! The cost is reasonable especially for the instruction you get-and WAY cheaper than the ripoff answer guides that the textbook business wants to force you to buy. Give this a month try and i promise you will want to keep using it. Huge help.

## Features

- 1,930 video solutions for
**all**regular problems in Giancoli's**7th Edition**and 1,681 solutions for most regular problems in the**6th Edition**. Final answer provided in text form for quick reference above each video, and formatted nicely as an equation, like $E=mc^2$. This is useful if you are in the library or have a slow internet connection.

- Pen colors make the step-by-step solutions clear. Red is used to illustrate algebra steps, and to substitute numeric values in the final step of a solution. When a solution switches to a new train of thought a different pen color emphasizes the switch, so that solutions are very methodical and organized.
- Solutions are classroom tested, and created by an experienced physics teacher.
- Videos are delivered with a high performance content delivery network. No waiting for videos to load or buffer.
- Pause, rewind, repeat, and never miss what is being said.

## Giancoli 7th Edition, Chapter 17, Problem 55

Thank you very much @holland016, I've updated the quick answer.

## Giancoli 7th Edition, Chapter 17, Problem 55

your answer for b is incorrect it should be 8x10*-11

## Giancoli 7th Edition, Chapter 4, Problem 23

@micisner, my pleasure, and it's great there is an easy fix!

## Giancoli 7th Edition, Chapter 2, Problem 13

Hi swedesanddanes, I'm guessing that the confusing part is the $x_{2i}$ in $x_2 = x_{2i} + v_2 t$, correct? For most questions it's typically enough to say something like $x_2 = v_2 t$, but the reason this is usually OK is that normally you choose the initial position to be zero, in which case $x_2 = x_{2i} + v_2 t$ would be the same as $x_2 = v_2 t$ since $x_{2i} = 0$ when the initial position is zero. This question, however, is not one of your usual questions. The second train begins at an initial position of $8.5 \textrm{ m}$, in which case $x_{2i} = 8.5 \textrm{ m}$, so this initial position term is needed in the position formula.

Just to check your understanding, notice how we could have instead chosen $x_{2i} = 0$ after all, but then the initial position of train 1 would need to be $x_{1i} = -8.5 \textrm{ m}$ (assuming positive is directed toward the right).

Hope this helps,

Mr. Dychko

## Giancoli 7th Edition, Chapter 4, Problem 23

You were totally right! My calculator was in radian. Thank you so much for your help.

Best,

Micisner