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Determine the magnitude and direction of the force on an electron traveling $7.75 \times 10^5 \textrm{ m/s}$ horizontally to the east in a vertically upward magnetic field of strength 0.45 T.

Source: Giancoli, Douglas C., Physics: Principles with Applications, 7th Edition, 2014.

Quick Answer: 

$5.6 \times 10^{-14} \textrm{ N North}$

Giancoli 7th Edition, Chapter 20, Problem 9


Chapter 20, Problem 9 is solved.

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