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  1. $1.19 \times 10^5 \textrm{ Pa, } 2.8 \times 10^7 \textrm{ N}$
  2. $1.19 \times 10^5 \textrm{ Pa}$

Giancoli 7th Global Edition, Chapter 10, Problem 16

(1:10)

Chapter 10, Problem 16 is solved.

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