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$F_{R_M} = 5.8 \times 10^{-4} \textrm{ N/m up}$
$F_{R_N} = 3.4 \times 10^{-4} \textrm{N/m, 60}^\circ\textrm{ below horizontal to the right}$
$F_{R_P} = 3.4 \times 10^{-4} \textrm{N/m, 60}^\circ\textrm{ below horizontal to the left}$

Giancoli 6th Edition, Chapter 20, Problem 45

(10:46)

Chapter 20, Problem 45 is solved.

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