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Which is better for resolving details of the nucleus: 25-MeV alpha particles or 25-MeV protons? Compare each of their wavelengths with the size of a nucleon in a nucleus.

Source: Giancoli, Douglas C., Physics: Principles with Applications, 7th Edition, 2014.

Quick Answer: 

$\lambda_{\alpha} = 2.88 \times 10^{-15} \textrm{ m, }$ $\lambda_{p} = 5.75 \times 10^{-15} \textrm{ m}$
The ratio of wavelength to the diameter of a nucleon is, for an alpha particle: $1.2$, whereas for a proton: $2.4$. The alpha particle will provide better resolution since it's wavelength is comparatively smaller.

Giancoli 7th Edition, Chapter 32, Problem 7


Chapter 32, Problem 7 is solved.

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