Giancoli 7th Edition textbook cover
Giancoli's Physics: Principles with Applications, 6th Edition
3
Kinematics in Two Dimensions; Vectors
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3-2 to 3-4: Vector Addition
3-5 and 3-6: Projectile Motion (neglect air resistance)
3-8: Relative Velocity

Problem 4
A
10.0 units 47 below positive x axis10.0 \textrm{ units } 47^\circ \textrm{ below positive x axis}
Giancoli 6th Edition, Chapter 3, Problem 4 solution video poster
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COMMENTS
By kaam.wilson on Sun, 3/10/2019 - 8:25 PM

Since the angle is in the fourth quadrant with y being negative and x being positive, shouldn't you add 47.4 to 270 degrees?

By Mr. Dychko on Sun, 3/10/2019 - 9:02 PM

Thanks for the question. If you want to express the angle in "standard position", which seems to be what you're after with adding something to 270 degrees, you would need to add (90-47.4) to 270. 90-47.4 gives the bit of angle between the terminal arm and the negative y-axis. This standard position angle (312.6 degrees) would be a fine answer as well.
Keep in mind that calculators usually give the "reference angle" (see https://brilliant.org/wiki/reference-angle/) which, in this case, is 47.4 degrees, and because of the way the angle is drawn, this angle is below the negative x-axis.

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