Giancoli's Physics: Principles with Applications, 6th Edition
8
Rotational Motion
Change chapter

8-1: Angular Quantities
8-2 and 8-3: Constant Angular Acceleration; Rolling
8-4: Torque
8-5 and 8-6: Rotational Dynamics
8-7: Rotational Kinetic Energy
8-8: Angular Momentum
8-9: Angular Quantities as Vectors

Problem 6
A
$3.7 \times 10^3 \textrm{rev}$

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By ankanguyen on Sun, 2/5/2012 - 8:29 PM

the answer should be 3.7E^4 not 3.7E^3

By Mr. Dychko on Thu, 3/29/2012 - 12:26 AM

Hi ankanguyen,

I ran the numbers again and still arrived at 3744 revolutions, so it looks like the answer is correct at 3.7E^3 revolutions. Is there something specific you noticed in the calculation?

By lweiss1 on Fri, 6/29/2012 - 6:08 PM

nevermind! sorry

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