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a) $\omega_p = \dfrac{-I_w \omega_w}{I_p}$
b) $\omega_p = \dfrac{-I_w \omega_w \cos{60}}{I_p}$
c) $\omega_p = \dfrac{I_w \omega_w}{I_p}$
d) the person will stop since the total angular momentum must be zero

Giancoli 6th Edition, Chapter 8, Problem 66

(6:36)

Chapter 8, Problem 66 is solved.

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