What is the sound level of a sound whose intensity is 1.5 x 10^{-6} W/m ^2?

This is Giancoli Answers with Mr. Dychko. Sound level in decibels is 10 times the logarithm of the sound intensity divided by the threshold of hearing intensity for a good ear. So, we have 10 times logarithm of 1.5 times 10 to the minus 6 watts per square meter divided by 1.0 times 10 to the minus 12 watts per square meter. And you get about 62 decibels.

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What is the sound level of a sound whose intensity is 1.5×10−6 W/m21.5 \times 10^{-6} \textrm{ W/m}^21.5×10−6 W/m2?

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What is the sound level of a sound whose intensity is $1.5 \times 10^{-6} \textrm{ W/m}^2$ ?