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  1. Show that the nucleus ${^{8}_{4}\textrm{Be}}$ (mass = 8.005305 u) is unstable and will decay into two $\alpha$ particles.
  2. Is ${^{12}_{6}\textrm{C}}$ stable against decay into three $\alpha$ particles? Show why or why not.

Source: Giancoli, Douglas C., Physics: Principles with Applications, 7th Edition, 2014.

Quick Answer: 
  1. Negative binding energy means ${}^8_4Be$ is unstable
  2. A positive binding energy means ${}^{12}_6C$ is stable against decay to ${}^4_2He$

Giancoli 7th Edition, Chapter 30, Problem 21


Chapter 30, Problem 21 is solved.

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