Giancoli 7th Edition textbook cover
Giancoli's Physics: Principles with Applications, 7th Edition

10-2: Density and Specific Gravity
10-3 to 10-6: Pressure; Pascal's Principle
10-7: Buoyancy and Archimedes' Principle
10-8 to 10-10: Fluid Flow, Bernoulli's Equation
10-11: Viscosity
10-12: Flow in Tubes; Poiseuille's Equation
10-13: Surface Tension and Capillarity
10-14: Pumps; the Heart

Question by Giancoli, Douglas C., Physics: Principles with Applications, 7th Ed., ©2014, Reprinted by permission of Pearson Education Inc., New York.
Problem 22
Q

An open-tube mercury manometer is used to measure the pressure in an oxygen tank. When the atmospheric pressure is 1040 mbar, what is the absolute pressure (in Pa) in the tank if the height of the mercury in the open tube is

  1. 18.5 cm higher,
  2. 5.6 cm lower, than the mercury in the tube connected to the tank? See Fig. 10–7a.
Pressure gauges: (a) open-tube manometer.
Figure 10-7 Pressure gauges: (a) open-tube manometer.
A
  1. 1.29×105 Pa1.29 \times 10^5 \textrm{ Pa}
  2. 9.7×104 Pa9.7 \times 10^4 \textrm{ Pa}
Giancoli 7th Edition, Chapter 10, Problem 22 solution video poster
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VIDEO TRANSCRIPT

This is Giancoli Answers with Mr. Dychko. Absolute pressure in an open tube monomer is atmospheric pressure plus the density of the fluid in the monomer times g times the height by which the fluid in the open end of the monomer is higher than the fluid in the end that's connected to whatever thing is having its pressure measured. So we have the pressure in the first case is 1040 millibar times 1.00 times 10 to the 2 pascals per millibar— that's atmospheric pressure— plus this additional pressure due to the column fluid there, mercury, 13.6 times 10 to the 3 kilograms per meter cubed for mercury times 9.8 newtons per kilogram times 18.5 times 10 to the minus 2 meters— that's centimeters converted into meters— and we get 1.29 times 10 to the 5 pascals must be the absolute pressure. And then when we have the column of... or the height difference in the monomer is 5.6 centimeters lower it's the same numbers except we have negative 5.6 times 10 to the minus 2 meters for the height here and this gives us a pressure lower than atmospheric pressure: 9.7 times 10 to the 4 pascals.

COMMENTS
By rdattafl on Thu, 2/2/2017 - 7:00 PM

In the video, you wrote 1.29 * 10^5 Pa, but in the main answer section, you wrote 1.20 * 10^5 Pa. Merely for clarity, can you correct the second answer?

By Mr. Dychko on Sun, 2/5/2017 - 8:25 PM

Thank you very much for spotting that rdattafl. I've updated the quick answer.

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