Giancoli 7th Edition textbook cover
Giancoli's Physics: Principles with Applications, 7th Edition

10-2: Density and Specific Gravity
10-3 to 10-6: Pressure; Pascal's Principle
10-7: Buoyancy and Archimedes' Principle
10-8 to 10-10: Fluid Flow, Bernoulli's Equation
10-11: Viscosity
10-12: Flow in Tubes; Poiseuille's Equation
10-13: Surface Tension and Capillarity
10-14: Pumps; the Heart

Question by Giancoli, Douglas C., Physics: Principles with Applications, 7th Ed., ©2014, Reprinted by permission of Pearson Education Inc., New York.
Problem 34
Q

An undersea research chamber is spherical with an external diameter of 5.20 m. The mass of the chamber, when occupied, is 74,400 kg. It is anchored to the sea bottom by a cable. What is

  1. the buoyant force on the chamber, and
  2. the tension in the cable?
A
  1. 7.40×105 N7.40 \times 10^5 \textrm{ N}
  2. 1.0×104 N1.0 \times 10^4 \textrm{ N}
Giancoli 7th Edition, Chapter 10, Problem 34 solution video poster
Padlock

In order to watch this solution you need to have a subscription.

VIDEO TRANSCRIPT

This is Giancoli Answers with Mr. Dychko. The buoyancy force equals the weight of the seawater displaced and that's gonna be the density of seawater multiplied by its volume which is the volume of the sphere times g and that's gonna be density of seawater times four-third's πr cubed— that's the volume of a sphere. So we have 1.025 times 10 to the 3 kilograms per cubic meter— density of seawater— times four-third's π times 5.2 meters divided by 2 to get the radius and cubed times 9.8 that gives 7.40 times 10 to the 5 newtons is the upwards buoyancy force. Now to find the tension force in this cable that's anchoring this thing to the seafloor we see that the tension down plus gravity down, it has to equal the buoyancy force upwards and so tension is buoyancy force minus gravity which is buoyancy force minus mg. And here's the buoyancy force we found already 7.3953 times 10 to the 5 newtons minus 74400 kilograms times 9.8 newtons per kilogram which gives 1.0 times 10 to the 4 newtons is the tension force.

Find us on:

Facebook iconTrustpilot icon
Giancoli Answers, including solutions and videos, is copyright © 2009-2024 Shaun Dychko, Vancouver, BC, Canada. Giancoli Answers is not affiliated with the textbook publisher. Book covers, titles, and author names appear for reference purposes only and are the property of their respective owners. Giancoli Answers is your best source for the 7th and 6th edition Giancoli physics solutions.