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Question: 

Red laser light from a He–Ne laser $(\lambda = 632.8 \textrm{ nm})$ creates a second-order fringe at $53.2 ^\circ$ after passing through the grating. What is the wavelength $\lambda$ of light that creates a first-order fringe at $20.6 ^\circ$?

Source: Giancoli, Douglas C., Physics: Principles with Applications, 7th Edition, 2014.

Quick Answer: 

556 nm

Giancoli 7th Edition, Chapter 24, Problem 35

(1:19)

Chapter 24, Problem 35 is solved.

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