$F_{fr}=9.8 \times 10^3N$ down along the ramp Giancoli 6th Edition, Chapter 5, Problem 22(10:57) Chapter 5, Problem 22 is solved. Start My Free Week View sample solution

## Comments

The video ends without solving the problem :(

Thanks for spotting that sroman. It's now fixed. =)

i thought there is a short cart to do it

Ffrx=cos(12)Fr-sin12Fr

therefore we can calculate the fraction directly

Correct answer is 9.8 x 10^3 N rather than 10^2 N.

Thanks okstate2015 for your sharp eye. In the very last step I made a mistake changing to scientific notation and should have written times 10^3 as you say. I've added the video to my "update" list.

How is 1200(26.39^2)/67=10,714 N?

This video has been updated!

I think I better look at this over and over again to really get it.