You are here

Sign up below or Log in to see this solution

Giancoli 6th Edition, Chapter 5, Problem 35


Sign up for Giancoli Answers

Visa Mastercard American Express Now accepting PayPal

Both plans include

  • Access to all available solutions for both the 7th and 6th Editions of Giancoli Physics: Principles with Applications
  • 7th Edition: 1,930 videos solving all regular problems in all 33 chapters.
  • 6th Edition: 1,681 video solutions covering every chapter.
  • Money back guarantee: If these solutions don't help with your studies, just contact me for a refund.

Or own the videos for offline viewing.

The DVD contains 1,930 videos solving the End-Of-Chapter Regular Problems in all 33 chapters of the 7th Edition of Giancoli's physics textbook "Physics: Principles With Applications". This covers both Volume 1 and Volume 2 of the textbook. The DVD does not include solutions to the End-Of-Chapter sections titled "Questions", "MisConceptual Questions", nor "General Problems". The 1,930 Regular Problems which are solved are the ones most commonly assigned for practice. Videos are in .mp4 format, organized by chapter. For quick reference, final answers are written .pdf form. This resource is the world's best guided practice for physics. Buy 7th Edition Videos

Have questions about our plans & pricing?

Do you offer a plan for schools?

Yes we do. This plan gives every student unlimited access to all videos using a single school login.

What type of payment methods to you accept?

Giancoli Answers accepts Visa, Mastercard, American Express and PayPal. For schools, a PO can be issued and payment is also possible by a physical cheque. Schools should get in touch to make arrangements for this.

How secure is my payment?

All payments are securely processed over HTTPS and your card information never touches the Giancoli Answers server. All payment processing is done by either Stripe or PayPal, both of which are highly respected for their secure practices. Extra technical note: when paying by credit card, the information is submitted using javascript directly from your web browser to Stripe. Stripe then returns a unique token usable only by Giancoli Answer to your browser. Your browser submits this token to the Giancoli Answers server, never the credit card number.

What is the cancellation policy?

Cancelling the monthly plan stops the auto-renewal of the subscription. You still keep access to the solutions until the date to which the plan is paid up. For instance, if you sign up on Sept. 1st, cancel on Sept. 15th, you would still have access until Oct. 1st. Cancellation does not delete your Giancoli Answers account and you can re-subscribe any time. The one year plan does not auto-renew, so cancellation isn't relevant to the one year plan.

What is the refund policy?

Your satisfaction is guaranteed. That's why refunds are always issued upon request. This is possible for payments made within the past 90 days for payments by credit card, or the past 60 days for payments by PayPal. These time limits are due to the payment processors.

Transcript for this Giancoli solution

So we’re told that at some position the acceleration due to gravity ‘g2’ equals a regular surface of the earth ‘g’ which is nine point eight divided by ten so where’s the acceleration due to gravity one tenth that that it has one the surface of the earth. So ‘g2’ is: ‘G’ times mass of the earth ‘mE’ divided by whatever that distance is which we have to find, ‘r2’ squared and that equals ‘G’ times mass of the earth ‘mE’ over radius of the earth ‘rE’ squared times one tenth. ‘G’ times ‘mE’ over ‘rE’ squared is ‘g’ on the earth’s surface so since the numerators are the same the denominators must also be the same including that ten there so we have: ‘r22’ equals ten times radius of the earth squared. Solving: ‘r2’ equals the square root of ten times the radius of the earth squared or we can write this as the square root of ten times the radius of the actual earth which is the square root of ten times six point three eight times ten raised to the power six meters which gives us two point zero times ten raise to the power seven meters. So at that distance from the center of the earth the acceleration due to gravity will be one tenth what it is on the surface of the earth.