Giancoli 7th Edition textbook cover
Giancoli's Physics: Principles with Applications, 7th Edition
DC Circuits
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19-1: Emf and Terminal Voltage
19-2: Resistors in Series and Parallel
19-3: Kirchhoff's Rules
19-4: Emfs Combined, Battery Charging
19-5: Capacitors in Series and Parallel
19-6: RC Circuits
19-8: Ammeters and Voltmeters

Question by Giancoli, Douglas C., Physics: Principles with Applications, 7th Ed., ©2014, Reprinted by permission of Pearson Education Inc., New York.
Problem 16
  1. the equivalent resistance of the circuit shown in Fig. 19–48,
  2. the voltage across each resistor, and
  3. the current through each resistor.
Problem 16.
Figure 19-48.
  1. 1350  Ω1350 \; \Omega
  2. V3=8.8 V, V1=V2=3.2 VV_3 = 8.8 \textrm{ V, } V_1 = V_2 = 3.2 \textrm{ V}
  3. I3=0.0089 A, I2=0.0047 A, I1=0.0042 AI_3 = 0.0089 \textrm{ A, } I_2 = 0.0047 \textrm{ A, } I_1 = 0.0042 \textrm{ A}
By Agp2196 on Sat, 3/21/2015 - 8:47 PM

I don't understand why those two are parallel and one is a series?

By Mr. Dychko on Sun, 3/22/2015 - 4:54 AM

Hi Agp2196, R1R_1 and R2R_2 can be recognized as in parallel since they have both ends connected by wires. The bottom ends are connected by a wire, and the top ends are also connected by a wire. This means current at the bottom, coming from the positive end of the battery, has a choice of R1R_1 or R2R_2, and when you see current being given this choice, you know the resistors are in parallel. Resistor labelled R3R_3 is in series since there are no other options but to go through R3R_3 in order to continue through the circuit.

Hope that helps,
Mr. Dychko

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