Giancoli 7th Edition textbook cover
Giancoli's Physics: Principles with Applications, 7th Edition
18
Electric Currents
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18-2 and 18-3: Electric Current, Resistance, Ohm's Law
18-4: Resistivity
18-5 and 18-6: Electric Power
18-7: Alternating Current
18-8: Microscopic View of Electric Current
18-10: Nerve Conduction

Question by Giancoli, Douglas C., Physics: Principles with Applications, 7th Ed., ©2014, Reprinted by permission of Pearson Education Inc., New York.
Problem 7
Q
  1. What is the current in the element of an electric clothes dryer with a resistance of 8.6  Ω8.6 \; \Omega when it is connected to 240 V?
  2. How much charge passes through the element in 50 min? (Assume direct current.)
A
  1. 28 A28 \textrm{ A}
  2. 8.4×104 C8.4 \times 10^4 \textrm{ C}
Giancoli 7th Edition, Chapter 18, Problem 7 solution video poster
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VIDEO TRANSCRIPT

This is Giancoli Answers with Mr. Dychko. The amount of current passing through the element of the closed dryer is given by this formula I equals V over R. Where we rearrange V equals IR by dividing both sides by R, then switching the sides around, we have I as V over R. So that's 240 volts divided by 8.6 ohms, which is about 28 amps. The amount of charge that passes in 50 minutes or we can rearrange this form. We know the current is the amount of charge that passes divided by time. And multiply both sides by t, then you get Q as current times time. That's 27.907 Coulombs per second that we figured out over here, writing Coulombs per second instead of amps. You can see that the seconds cancel here leaving us with Coulombs. Or we multiply them by 15 minutes converted into seconds by multiplying by 60 seconds per minute. We have 8.4 times 10 to the four Coulombs of charge to pass through the dryer element.

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