is the separation of the two H atoms. The binding energy (the energy difference between PE = 0 and the lowest energy state near the bottom of the well) is 4.5 eV, and

r_0 = 0.074 \textrm{ nm}

$\Delta E = 1.5 \times 10^{-2} \textrm{ eV, } \lambda = 82 \; \mu \textrm{m}$
$\Delta E = 3.0 \times 10^{-2} \textrm{ eV, } \lambda = 41 \; \mu \textrm{m}$
$\Delta E = 4.5 \times 10^{-2} \textrm{ eV, } \lambda = 27 \; \mu \textrm{m}$

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The equilibrium separation of H atoms in the H2\textrm{H}_2H2​ molecule is 0.074 nm (Fig. 29–8). Calculate the energies and wavelengths of photons for the rotational transitions

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The equilibrium separation of H atoms in the $\textrm{H}_2$ molecule is 0.074 nm (Fig. 29–8). Calculate the energies and wavelengths of photons for the rotational transitions