Giancoli 7th Edition textbook cover
Giancoli's Physics: Principles with Applications, 7th Edition
11
Vibration and Waves
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11-1 to 11-3: Simple Harmonic Motion
11-4: Simple Pendulum
11-7 and 11-8: Waves
11-9: Energy Transported by Waves
11-11: Interference
11-12: Standing Waves; Resonance
11-13: Refraction
11-14: Diffraction

Question by Giancoli, Douglas C., Physics: Principles with Applications, 7th Ed., ©2014, Reprinted by permission of Pearson Education Inc., New York.
Problem 42
Q

A sailor strikes the side of his ship just below the surface of the sea. He hears the echo of the wave reflected from the ocean floor directly below 2.4 s later. How deep is the ocean at this point?

A
1700 m1700 \textrm{ m}
Giancoli 7th Edition, Chapter 11, Problem 42 solution video poster
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VIDEO TRANSCRIPT

This is Giancoli Answers with Mr. Dychko. The speed of a longitudinal wave in the liquid is the square root of the bulk modulus of the liquid divided by its density. And we have for this sound wave going from the ship to the sea floor and back, it's going to travel a total of 2 times the depth of the water and that's going to equal its speed times the time. So, we'll solve this for d divide both sides by 2 and then also substitute for v square root p modulus divided by density. And that gives 2.4 seconds over 2 times square root of 2 times 10 to the 9 newtons per square meter divided by 1 times 10 to the 3 kilograms per cubic meter which gives about 1700 meters must be the depth of the water.

COMMENTS
By esteedance1313 on Tue, 3/16/2021 - 8:35 PM

How did you find the values for B and P?

By Hardt99 on Fri, 4/9/2021 - 4:45 PM

Be mindful that saltwater has a different density than freshwater. Saltwater's is 1.025 x 10^3.

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