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  4. Problem 13
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Question: 

Express the following using the prefixes of Table 1–4:

  1. $1 \times 10^6 \textrm{ volts}$,
  2. $2 \times 10^{-6} \textrm{ meters}$,
  3. $6 \times 10^3 \textrm{ days}$,
  4. $18 \times 10^2 \textrm{ bucks}$, and
  5. $7 \times 10^{-7} \textrm{ seconds}$.

Giancoli, Douglas C., Physics: Principles with Applications, 7th Ed., ©2014. Reprinted by permission of Pearson Education Inc., New York.
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Quick Answer: 

a) $1 \textrm{ MV}$ b) $2 \textrm{ }\mu\textrm{m}$
c) $6 \textrm{ kdays}$
d) $18 \textrm{ hbucks}$
e) $700 \textrm{ ns}$

Giancoli 7th Edition, Chapter 1, Problem 13

(1:18)

Chapter 1, Problem 13 is solved.

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Transcript for this Giancoli solution

This is Giancoli Answers with Mr. Dychko. Times 10 to the 6 gets the prefix mega so we have 1 megavolt in part (a). Times 10 to the minus 6 is the prefix micro so we have 2 micrometers in part (b). 10 to the positive 3 is kilo so we have 6 kilodays, 6000 days. In part (d), we have 10 to the 2 is hecto so we have 18 hectobucks. And then part (e), 7 times 10 to the minus 7 there is no prefix just for 10 to the minus 7 so we have to kind of use one of the others; you could have either used nano or micro I used nanoseconds which is times 10 to the minus 9 but we have 10 to the minus 7 here so we'll have to multiply this number by a hundred or 10 to the 2 in order for 10 to the 2 times 10 to the minus 9 to work out to 10 to the minus 7 that we started with so you can say 700 nanoseconds; you could have also said 0.7 microseconds would also work.