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Quick Answer: 
  1. $1.5 \times 10^{-4} \textrm{ rad/s}^2$
  2. $a_T = 6.2 \times 10^{-4} \textrm{ m/s}^2 \textrm{, } a_R = 1.2 \times 10^{-2} \textrm{ m/s}^2$

Giancoli 7th Edition, Chapter 8, Problem 15

(2:30)

Chapter 8, Problem 15 is solved.

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