Giancoli's Physics: Principles with Applications, 7th Edition
8
Rotational Motion
Change chapter8-1: Angular Quantities
8-2 and 8-3: Constant Angular Acceleration; Rolling
8-4: Torque
8-5 and 8-6: Rotational Dynamics
8-7: Rotational Kinetic Energy
8-8: Angular Momentum
8-9: Angular Quantities as Vectors
Question by Giancoli, Douglas C., Physics: Principles with Applications, 7th Ed., ©2014, Reprinted by permission of Pearson Education Inc., New York.
Problem 31
Q
Estimate the moment of inertia of a bicycle wheel 67 cm in diameter. The rim and tire have a combined mass of 1.1 kg. The mass of the hub (at the center) can be ignored (why?).
A
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VIDEO TRANSCRIPT
This is Giancoli Answers with Mr. Dychko. The moment of inertia for this bicycle wheel can be calculated using this formula for the moment of inertia of a thin hoop—its mass times its radius squared. So it's 1.1 kilograms—combined mass of the rim and tyre— times by the diameter of 67 centimeters expressed in meters and then divide that by 2 to get the radius and then square that and you get 0.12 kilogram meter squared. And the moment of inertia of the hub can be ignored because it's so close to the center that its radius will be really small and so its contribution to the moment of inertia will also be really small.
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