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Quick Answer: 

$F_{top} = 2.00 \times 10^2 \textrm{ N up, }$
$F_{BL} = 2.00 \times 10^2 \textrm{ N } 30^\circ \textrm{ below the negative } x \textrm{ axis.}$
$F_{BR} = 2.00 \times 10^2 \textrm{ N } 30^\circ \textrm{ below the positive } x \textrm{ axis.}$

Giancoli 7th Edition, Chapter 16, Problem 12

(7:30)

Chapter 16, Problem 12 is solved.

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Comments

I think the third charge should also be 2*10^2, typo probably?

Hi dewald, thanks for spotting that, and you're quite right. I've updated the quick text answer to reflect the correct answer in the video.

All the best,
Mr. Dychko

Hi Mr. Dychko,

Could you please also show the solution using vector addition?

Thank you so much!

Hi Angie, thanks for the request. Unfortunately I'm away from my recording equipment at the moment. Vector addition is definitely an important technique. I use it in many other solution videos, so hopefully you can see the technique there?

Best wishes with your studies,
Mr. Dychko