Giancoli's Physics: Principles with Applications, 7th Edition

16

Electric Charge and Electric Field

Change chapter16-5 and 16-6: Coulomb's Law

16-7 and 16-8: Electric Field, Field Lines

16-10: DNA

16-12: Gauss's Law

Question by Giancoli, Douglas C., Physics: Principles with Applications, 7th Ed., ©2014, Reprinted by permission of Pearson Education Inc., New York.

Problem 3

Q

A

$2.2 \times 10^4 \textrm{ N}$

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VIDEO TRANSCRIPT

This is Giancoli Answers with Mr. Dychko. The magnitude of the force is given by Coulomb's Law. So we have Coulomb's constant 8.988 times 10 to the nine Newton meters squared per Coulomb squared, times by one charge which is 25 microcoulomb's, and we used 10 to the minus six in place of the micro. And then the other charge is 2.5 millicoulombs, and that prefix milli means times 10 the minus three. Then we divide it by the distance between them which is 16 centimeters which we converted to meters by multiplying by 10 to the minus two, and square that. And we get about 2.2 times 10 the 4 in Newtons is the magnitude of the force between these two charges.

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