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Quick Answer: 

$1.15 \times 10^6 \textrm{ N/C toward the } -38.6 \mu\textrm{C charge.}$

Giancoli 7th Edition, Chapter 16, Problem 30

(3:33)

Chapter 16, Problem 30 is solved.

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Comments

Hi Professor Dychko,
I'm confused on why you would not solve for the x and y components of both electric fields and then take the magnitude of the net electric field.
Thanks!

Hi Professor Dychko,
I'm confused on why you would not solve for the x and y components of both electric fields and then take the magnitude of the net electric field.
Thanks!