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Quick Answer: 
  1. $\dfrac{Q}{4\pi r^2 \epsilon_o}$
  2. Zero
  3. $\dfrac{Q}{4\pi r^2 \epsilon_o}$
  4. the shell has no effect on the field due to the charge, with the exception of within the thickness of the shell material where there is no field at all. The charge creates a charge distribution across the thickness of the shell.

Giancoli 7th Edition, Chapter 16, Problem 43

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Chapter 16, Problem 43 is solved.

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