Giancoli 7th Edition textbook cover
Giancoli's Physics: Principles with Applications, 7th Edition
Electric Charge and Electric Field
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Question by Giancoli, Douglas C., Physics: Principles with Applications, 7th Ed., ©2014, Reprinted by permission of Pearson Education Inc., New York.
Problem 38

The total electric flux from a cubical box of side 28.0 cm is 1.85×103 Nm2/C1.85 \times 10^3 \textrm{ N}\cdot\textrm{m}^2\textrm{/C}. What charge is enclosed by the box?

1.64×108 C1.64 \times 10^{-8} \textrm{ C}
Giancoli 7th Edition, Chapter 16, Problem 38 solution video poster

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This is Giancoli Answers with Mr. Dychko. Total electric flux equals the enclosed charge within this Gaussian surface divided by the permittivity of free space. And we're told that the total flux is 1.85 times 10 to the three Newton meters squared per Coulomb. So we can multiply each of this by Ε naught. And we get the enclosed charge is permittivity of free space times this total flux. That's 8.85 times 10 to the minus 12 Coulombs squared per Newton meter squared, times 1.85 times 10 to the three Newton meters squared per Coulomb, and we get 1.64 times 10 to the negative eight Coulombs must be the enclosed charge.

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