Giancoli's Physics: Principles with Applications, 7th Edition
17
Electric Potential
Change chapter17-1 to 17-4: Electric Potential
17-5: Potential Due to Point Charges
17-6: Electric Dipoles
17-7: Capacitance
17-8: Dielectrics
17-9: Electric Energy Storage
17-10: Digital
17-11: TV and Computer Monitors
Question by Giancoli, Douglas C., Physics: Principles with Applications, 7th Ed., ©2014, Reprinted by permission of Pearson Education Inc., New York.
Problem 13
Q
What is the speed of a proton whose KE is 4.2 keV?
A
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VIDEO TRANSCRIPT
This is Giancoli Answers with Mr. Dychko. Kinetic energy is one-half mass times velocity squared. And if you multiply both sides by two and divide both sides by m, and then take the square root of both sides, you get that the speed is square root of two times kinetic energy divided by mass. So that's two times 4.2 times 10 to the three electron volts, convert it into Joules by multiplying by 1.602 times 10 to the minus 19 Joules per electron volt. Then divided by the mass of a proton, 1.67 times 10 to the negative 27 kilograms. Then you get both 9.0 times 10 to the five meters per second when you round the two significant figures.
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