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Giancoli 7th Edition textbook cover
Giancoli's Physics: Principles with Applications, 7th Edition
17
Electric Potential
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17-1 to 17-4: Electric Potential
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17-5: Potential Due to Point Charges
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17-6: Electric Dipoles
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17-7: Capacitance
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17-8: Dielectrics
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17-9: Electric Energy Storage
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17-10: Digital
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17-11: TV and Computer Monitors
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Question by Giancoli, Douglas C., Physics: Principles with Applications, 7th Ed., ©2014, Reprinted by permission of Pearson Education Inc., New York.
Problem 47
Q

What is the capacitance of two square parallel plates 6.6 cm on a side that are separated by 1.8 mm of paraffin?

A
4.7×10−11 F4.7 \times 10^{-11} \textrm{ F}
Giancoli 7th Edition, Chapter 17, Problem 47 solution video poster
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VIDEO TRANSCRIPT

This is Giancoli Answers with Mr. Dychko. Capacitance equals the dielectric constant times the permittivity of free space times the area of the plates divided by separation. So the dielectic constant for paraffin is 2.2 multiplied by 8.85 times ten to the minus 12 for the permittivity of free space times 6.6 times ten to the minus two meters and then square that and divide by the separation between the plates of 1.8 times ten to the minus three meters. This gives 4.7 times ten to the minus 11 farads for the capacitance.

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Giancoli Answers, including solutions and videos, is copyright © 2009-2024 Shaun Dychko, Vancouver, BC, Canada. Giancoli Answers is not affiliated with the textbook publisher. Book covers, titles, and author names appear for reference purposes only and are the property of their respective owners. Giancoli Answers is your best source for the 7th and 6th edition Giancoli physics solutions.