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$-0.56 g's$

Giancoli 6th Edition, Chapter 2, Problem 19

(1:27)

Chapter 2, Problem 19 is solved.

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Transcript for this Giancoli solution

The acceleration is: change in velocity over time, the final velocity is zero because it comes to a stop and the initial velocity is one hundred and ten meters divided by five point zero seconds which is twenty two meters per second. The acceleration is: final velocity minus initial velocity over time so that’s zero meters per second minus twenty two meters per second divided by four point zero seconds equaling negative five point five meters per second squared. It wants us to give the units in ‘g’s so well say acceleration is: negative five point five meters per second squared times one ‘g’ for every nine point eight meters per second squared. Considering them as a single package, meters per second squared in the numerator cancel with meters per second squared in the denominator leaving us with ‘g’s as our units, which is what we want. So it’s going to be negative zero point five six ‘g’s.