Giancoli 7th Edition textbook cover
Giancoli's Physics: Principles with Applications, 7th Edition
Work and Energy
Change chapter

6-1: Work, Constant Force
6-2: Work, Varying Force
6-3: Kinetic Energy; Work-Energy Principle
6-4 and 6-5: Potential Energy
6-6 and 6-7: Conservation of Mechanical Energy
6-8 and 6-9: Law of Conservation of Energy
6-10: Power

Question by Giancoli, Douglas C., Physics: Principles with Applications, 7th Ed., ©2014, Reprinted by permission of Pearson Education Inc., New York.
Problem 15

At room temperature, an oxygen molecule, with mass of 5.31×1026 kg5.31 \times 10^{-26} \textrm{ kg}, typically has a kinetic energy of about 6.21×1021 J6.21 \times 10^{-21} \textrm{ J}. How fast is it moving?

484 m/s484 \textrm{ m/s}
Giancoli 7th Edition, Chapter 6, Problem 15 solution video poster

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This is Giancoli Answers with Mr. Dychko. Kinetic energy is one-half mass times velocity squared and we can solve for v by multiplying both sides by 2 over m and then we take the square root of both sides and we get v. So v is the square root of 2 times kinetic energy divided by mass so that's square root of 2 times the kinetic energy of 6.21 times 10 to the minus 21 joules, for an oxygen molecule, divided by an oxygen molecule's mass of 5.31 times 10 to the negative 26 kilograms that gives us speed of about 484 meters per second.

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