Giancoli's Physics: Principles with Applications, 7th Edition
6
Work and Energy
Change chapter6-1: Work, Constant Force
6-2: Work, Varying Force
6-3: Kinetic Energy; Work-Energy Principle
6-4 and 6-5: Potential Energy
6-6 and 6-7: Conservation of Mechanical Energy
6-8 and 6-9: Law of Conservation of Energy
6-10: Power
Question by Giancoli, Douglas C., Physics: Principles with Applications, 7th Ed., ©2014, Reprinted by permission of Pearson Education Inc., New York.
Problem 18
Q
How much work must be done to stop a 925-kg car traveling at 95 km/h?
A
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VIDEO TRANSCRIPT
This is Giancoli Answers with Mr. Dychko. The net work done on a car is equal to its change in kinetic energy so that's the final kinetic energy minus the initial kinetic energy. But it comes to a rest and so there's no final kinetic energy so we just have net work is negative one-half m v initial squared. This negative one-half times 925 kilograms and times the speed, converted into meters per second, that's 95 kilometers per hour times 1 hour for every 3600 seconds times 1000 meters per kilometer, giving us meters per second, and we end up with negative 3.2 times 10 to the 5 joules of net work done on the car.
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