This is Giancoli Answers with Mr. Dychko. We can solve this formula for heat gain by a substance for c the specific heat capacity by dividing both sides by mass times change in temperature. So, c is Q over m ΔT, and it absorbs 135 times 10 to the 3 joules divided by 4.1 kilograms times 37.2 degrees Celsius, final temperature, minus 18 degrees Celsius, initial temperature. And we get about 1.7 times 10 to the 3 joules per kilogram Celsius degree is the specific heat capacity of this metal.

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What is the specific heat of a metal substance if 135 kJ of heat is needed to raise 4.1 kg of the metal from 18.0∘C18.0 ^\circ \textrm{C}18.0∘C to 37.2∘C37.2 ^\circ \textrm{C}37.2∘C?

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What is the specific heat of a metal substance if 135 kJ of heat is needed to raise 4.1 kg of the metal from $18.0 ^\circ \textrm{C}$ to $37.2 ^\circ \textrm{C}$ ?