You are here


If $3.40 \times 10^5 \textrm{ J}$ of energy is supplied to a container of liquid oxygen at $-183 ^\circ \textrm{C}$, how much oxygen can evaporate?

Giancoli, Douglas C., Physics: Principles with Applications, 7th Ed., ©2014. Reprinted by permission of Pearson Education Inc., New York.
The question will be visible after logging in, as required by Pearson Education Inc.

Quick Answer: 

$1.6 \textrm{ kg}$

Giancoli 7th Edition, Chapter 14, Problem 24


Chapter 14, Problem 24 is solved.

View sample solution

Transcript for this Giancoli solution

This is Giancoli Answers with Mr. Dychko. The amount of heat needed to change phase of a certain mass of the substance is the mass times the latent heat of vaporization in this case because it's going from a liquid to a gas. So, we'll divide both sides by L to solve for m. So, the amount of mass that can turn into gas is going to be the energy absorbed which is 3.4 times 10 to the 5 joules divided by the latent heat of vaporization for oxygen which is 210 times 10 to the 3 joules per kilogram which is about 1.6 kilograms.


How did you get 2.1x10^5 j/kg? That number is not in the problem.

This number is found in a data table 14-3 titled "Latent Heats" on page 397. It's the latent heat of vaporization for oxygen.