Giancoli's Physics: Principles with Applications, 7th Edition
2
Describing Motion: Kinematics in One Dimension
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2-1 to 2-3: Speed and Velocity
2-4: Acceleration
2-5 and 2-6: Motion at Constant Acceleration
2-7: Freely Falling Objects
2-8: Graphical Analysis

Question by Giancoli, Douglas C., Physics: Principles with Applications, 7th Ed., ©2014, Reprinted by permission of Pearson Education Inc., New York.
Problem 17
Q

# A sports car accelerates from rest to 95 km/h in 4.3 s. What is its average acceleration in $\textrm{m/s}^2$?

A
$6.1\textrm{ m/s}^2$

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VIDEO TRANSCRIPT

This is Giancoli Answers with Mr. Dychko. The acceleration of the sports car will be its change in velocity divided by time. So change of velocity is the final velocity minus the initial velocity and well the initial velocity is zero so the change in velocity is just gonna be the final velocity. And so that's gonna be 95 kilometers an hour which we convert into meters per second by multiplying by 1 hour for every 3600 seconds and times by 1000 meters for every kilometer giving us meters per second and that's 26.3889 meters per second. So we take that, divide it by 4.3 seconds and that gives us 6.1 meters per second every second or 6.1 meters per second squared acceleration.

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