Giancoli 7th Edition textbook cover
Giancoli's Physics: Principles with Applications, 7th Edition
15
The Laws of Thermodynamics
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15-1 and 15-2: First Law of Thermodynamics
15-3: Human Metabolism
15-5: Heat Engines
15-6: Refrigerators, Air Conditioners, Heat Pumps
15-7: Entropy
15-10: Statistical Interpretation
15-11: Energy Resources

Question by Giancoli, Douglas C., Physics: Principles with Applications, 7th Ed., ©2014, Reprinted by permission of Pearson Education Inc., New York.
Problem 20
Q

The exhaust temperature of a heat engine is 230C230 ^\circ \textrm{C}. What is the high temperature if the Carnot efficiency is 34%?

A
490C490^\circ\textrm{C}
Giancoli 7th Edition, Chapter 15, Problem 20 solution video poster
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VIDEO TRANSCRIPT

This is Giancoli Answers with Mister Dychko. Carnot efficiency is the ideal efficiency and it's one minus the low temperature reservoir divided by the temperature of the high temperature reservoir. We can rearrange this a little bit by taking this to the left hand side which makes it positive and then take this to the right hand side making it Tl over Th equal one minus efficiency. Then we can take the reciprocal of both sides so we raise both sides to the exponent negative one and that flips the left side. So, Th over Tl and the right hand side starts off as one minus e all over one and then when you flip it, it becomes one over one minus e. And then multiply both sides by T low and you get the high temperature is the low temperature divided by one minus e. The temperature always has to be in Kelvin so that's 230 degrees Celsius plus 273 to convert into Kelvin divided by one minus 0.34 and you get about 490 degrees Celsius after you subtract 273 away from this answer in Kelvin.

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