Water is stored in an artificial lake created by a dam (Fig. 15–27). The water depth is 48 m at the dam, and a steady flow rate of 32 m ^3 /s is maintained through hydroelectric turbines installed near the base of the dam. How much electrical power can be produced?

This is Giancoli answers with Mr. Dychko. Assuming perfect efficiency, the power output of this hydro-dam will be the gravitational potential energy of water divided by time, so its energy per time and so this is mass divided by time times gravitational field strength times the height of the water. So we have 32 cubic meters per second and then we have to convert that cubic meters into, into kg and we can change a cubic, cubic metres into liters by multipliying by one liter for every point 0.001 cubic meters and then multiply by the density of water which is one kilogram per litre. And since now we have kilogram per second and times by 9.8 newtons per kilogram times 48 meters height. And that's 1.5 times ten to the seven watts which is about 15 megawatts.

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Water is stored in an artificial lake created by a dam (Fig. 15–27). The water depth is 48 m at the dam, and a steady flow rate of 32 m3/s32 \textrm{ m}^3 \textrm{/s}32 m3/s is maintained through hydroelectric turbines installed near the base of the dam. How much electrical power can be produced?

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Water is stored in an artificial lake created by a dam (Fig. 15–27). The water depth is 48 m at the dam, and a steady flow rate of $32 \textrm{ m}^3 \textrm{/s}$ is maintained through hydroelectric turbines installed near the base of the dam. How much electrical power can be produced?