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Giancoli 7th Edition textbook cover
Giancoli's Physics: Principles with Applications, 7th Edition
15
The Laws of Thermodynamics
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15-1 and 15-2: First Law of Thermodynamics
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15-3: Human Metabolism
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15-5: Heat Engines
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15-6: Refrigerators, Air Conditioners, Heat Pumps
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15-7: Entropy
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15-10: Statistical Interpretation
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15-11: Energy Resources
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Question by Giancoli, Douglas C., Physics: Principles with Applications, 7th Ed., ©2014, Reprinted by permission of Pearson Education Inc., New York.
Problem 21
Q

A heat engine does 9200 J of work per cycle while absorbing 25.0 kcal of heat from a high-temperature reservoir. What is the efficiency of this engine?

A
8.8%8.8\%
Giancoli 7th Edition, Chapter 15, Problem 21 solution video poster
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VIDEO TRANSCRIPT

This is Giancoli Answers with Mister Dychko. Efficiency is the work done by the engine divided by the amount of heat added to heat from the high temperature reservoir. That's 9200 joules of work done divided by 25 kilocalories of heat absorbed. We convert that into joules by multiplying by 4.186 times ten to the three joules per kilocalorie and we get 8.8 percent efficiency.

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Giancoli Answers, including solutions and videos, is copyright © 2009-2024 Shaun Dychko, Vancouver, BC, Canada. Giancoli Answers is not affiliated with the textbook publisher. Book covers, titles, and author names appear for reference purposes only and are the property of their respective owners. Giancoli Answers is your best source for the 7th and 6th edition Giancoli physics solutions.