Good question. It is not possible to cancel the m's. Doing so is a common type of algebra mistake. "cancelling" really means dividing every term on the top by the bottom, so if you tried cancelling the m's, you would end up with $\dfrac{F_c}{m} - g$. Notice that, which the m's did cancel from the second term, the 'm' is still hanging around under the Fc term.

## Comments

Hi,

I'm just wondering, couldn't the m's in the step (Fc-m*g)/m cancel out?

Thanks

Hi jtorres89,

Good question. It is not possible to cancel the m's. Doing so is a common type of algebra mistake. "cancelling" really means dividing every term on the top by the bottom, so if you tried cancelling the m's, you would end up with $\dfrac{F_c}{m} - g$. Notice that, which the m's did cancel from the second term, the 'm' is still hanging around under the Fc term.