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$W_g=7.27 \times 10^3 J$

Giancoli 6th Edition, Chapter 6, Problem 1

(1:10)

Chapter 6, Problem 1 is solved.

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Transcript for this Giancoli solution

This pile driver can do as much work as the work done on it by gravity. So the work done on this pile driver by gravity is equal to the force of gravity which is 'mg' and then we’ll multiply that by the distance that it falls. First let’s figure out the force. That’s 265 kilograms times 9.8 newtons per kilogram and that is 2,597 newtons. And the distance over which this force is acting is 2.8 meters because that’s how far it falls. So work done by gravity is the force of gravity times the displacement. These are parallel so we don’t have to worry about any directions at all here. So we have that force times 2.8 meters and we get the work done, ### times ## to the # joules.

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