### Sign up below or Log in to see this solution

## Sign up for Giancoli Answers

### Monthly

### One Year

#### Both plans include

- Access to all available solutions for both the 7th and 6th Editions of Giancoli Physics: Principles with Applications
**7th Edition:**1,930 videos solving**all**regular problems in all 33 chapters.**6th Edition:**1,681 video solutions covering every chapter.- Money back guarantee: If these solutions don't help with your studies, just contact me for a refund.

## Have questions about our plans & pricing?

### What type of payment methods to you accept?

Giancoli Answers accepts Visa, Mastercard, American Express and PayPal. For schools, a PO can be issued and payment is also possible by a physical cheque. Schools should get in touch to make arrangements for this.

### How secure is my payment?

All payments are securely processed over HTTPS and your card information never touches the Giancoli Answers server. All payment processing is done by either Stripe or PayPal, both of which are highly respected for their secure practices. Extra technical note: when paying by credit card, the information is submitted using javascript directly from your web browser to Stripe. Stripe then returns a unique token usable only by Giancoli Answer to your browser. Your browser submits this token to the Giancoli Answers server, never the credit card number.

### What is the cancellation policy?

Cancelling the monthly plan stops the auto-renewal of the subscription. You still keep access to the solutions until the date to which the plan is paid up. For instance, if you sign up on Sept. 1st, cancel on Sept. 15th, you would still have access until Oct. 1st. Cancellation does not delete your Giancoli Answers account and you can re-subscribe any time. The one year plan does not auto-renew, so cancellation isn't relevant to the one year plan.

### What is the refund policy?

Your satisfaction is guaranteed. That's why refunds are always issued upon request. This is possible for payments made within the past 90 days for payments by credit card, or the past 60 days for payments by PayPal. These time limits are due to the payment processors.

### Transcript for this Giancoli solution

So here's the figure in the text book. For part A we're finding the work done between zero and ten seconds, and we'll find that by calculating this area 'A1' plus 'A2' plus 'A3'. We could use a trapezoid formula for this one, but maybe it’s a little more obvious why it's this triangle 'A1' plus this triangle 'A2' plus this triangle 'A3'. We can calculate it anyway we like. So we have the work done is 'A1' plus 'A2' plus 'A3'. Area of a triangle is one half base times height, and the way I see it, this point lines up with 3 meters and 400 newtons. We have another point lining up at seven meters and 400 newtons and the whole thing ends at ten seconds. So 'A1' is one half times the base being 3 meters times the height of 400 newtons, plus area two is 4 meters. That’s the difference between seven and three, times the height of 400 newtons. Then 'A3' is one half times three meters again, that’s the difference between 10 and 7. Times the height of 400 newtons, this gives an answer for part A of 2,800 joules of work done between zero and ten seconds.In part B we calculate the work done for the entire time from zero to 15 seconds. And we can see that there is some negative work being done here because the force is going against the direction of motion. So that’s going to reduce the total work done, so we'll be subtracting those areas. So we'll call that area four, area five and area six. So the work done in part B is going to be 'A1' plus 'A2' plus 'A3' minus 'A4' minus 'A5' and 'A6'. So 'a1' 2 and 3 we already know is 2,800 so let's just write that down. And then we're going to subtract away between 10 and 12 that’s two seconds, so that’s the base, is two. And we'll multiply that by a height of 200. I've already got the negative sign accounted for here, so we don’t need to go negative 200.

So we have two times 200 newtons, that’s 2 meters times 200 newtons divided by 2 minus 1.5 meters times 200 newtons, that’s the little rectangle. That’s this 'A5', that’s 1.5 times 200 newtons. And then we'll also subtract away the last triangle there, 'A6'. So we have one and a half meters times 200 newtons divided by two. And the answer here, total work done from zero to fifteen seconds is approximately 2,150 joules.