$\Delta PE = 2.5 \times 10^3J$ Giancoli 6th Edition, Chapter 6, Problem 28(0:32) Chapter 6, Problem 28 is solved. Start My Free Week View sample solution Transcript for this Giancoli solution The change in potential energy of this pole vaulter is equal to ‘mgh’. And so we substitute in numbers; 64 kilograms times 9.8 Newtons per kilogram times four meters that the pole vault goes up and that gives us ANSWER Joules.