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$\Delta PE = 2.5 \times 10^3J$

Giancoli 6th Edition, Chapter 6, Problem 28


Chapter 6, Problem 28 is solved.

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Transcript for this Giancoli solution

The change in potential energy of this pole vaulter is equal to ‘mgh’. And so we substitute in numbers; 64 kilograms times 9.8 Newtons per kilogram times four meters that the pole vault goes up and that gives us ANSWER Joules.