Question:

A projectile is fired with an initial speed of 36.6 m/s at an angle of $42.2^\circ$ above the horizontal on a long flat firing range. Determine

- the maximum height reached by the projectile,
- the total time in the air,
- the total horizontal distance covered (that is, the range), and
- the speed of the projectile 1.50 s after firing.

Giancoli, Douglas C., Physics: Principles with Applications, 7th Ed., ©2014. Reprinted by permission of Pearson Education Inc., New York.

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Quick Answer:

- $30.8\textrm{ m}$
- $5.02\textrm{ s}$
- $136\textrm{ m}$
- $28.9\textrm{ m/s}$

## Comments

1. why is it 36.6m/s(sin42)-(9.80)(1.50), doesnt the equation say V0sin+ayt?

2. how did you obtain 27.113m/s^2 for Vx?