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A diver leaves the end of a 4.0-m-high diving board and strikes the water 1.3 s later, 3.0 m beyond the end of the board. Considering the diver as a particle, determine:

  1. her initial velocity, $\vec{V} \!_0$;
  2. the maximum height reached; and
  3. the velocity $\vec{V} \!_f$ with which she enters the water.

Source: Giancoli, Douglas C., Physics: Principles with Applications, 7th Edition, 2014.

Quick Answer: 
  1. $4.0\textrm{ m/s}$
  2. $4.6\textrm{ m}$
  3. $9.7 \textrm{ m/s, } 76^\circ\textrm{ below horizon}$

Giancoli 7th Edition, Chapter 3, Problem 33


Chapter 3, Problem 33 is solved.

View sample solution


In the beginning when we solved for the Vx Initial and got 2.3077 why did we also use that in the magnitude calculation in the end? We solved for a final velocity of y, but we reused the velocity of x, could you please explain. Thanks.

Hi Icbishop, thanks for the question. Just to be clear, we're talking about part a), right? In part a) we solved for the resultant velocity, which is to say we solved for the vector sum of the x and y components. The answer for part a) is not the final velocity of y, but rather the final resultant velocity, which is normally just referred to as the velocity, but I'm including the word resultant to answer your question by explaining that the velocity is arrived at by using the pythagorean theorem to get it's magnitude by taking the square root of the sum of the squares of the x and y components of the velocity, and using trigonometry to get the direction.

Hope that helps,
Mr. Dychko