Giancoli's Physics: Principles with Applications, 7th Edition

13

Temperature and Kinetic Theory

Change chapter13-1: Atomic Theory

13-2: Temperature and Thermometers

13-4: Thermal Expansion

13-5: Gas Laws; Absolute Temperature

13-6 and 13-7: Ideal Gas Law

13-8: Ideal Gas Law in Terms of Molecules; Avogadro's Number

13-9: Molecular Interpretation of Temperature

13-11: Real Gases; Phase Changes

13-12: Vapor Pressure and Humidity

13-13: Diffusion

Question by Giancoli, Douglas C., Physics: Principles with Applications, 7th Ed., ©2014, Reprinted by permission of Pearson Education Inc., New York.

Problem 21

Q

A

$-459.67^\circ\textrm{F}$

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VIDEO TRANSCRIPT

This is Giancoli Answers with Mr. Dychko. Temperature in kelvin is 273.15 more than the temperature in Celsius. And so we can find the temperature in Celsius is can be temperature in kelvin minus 273.15. And then we have this formula for the temperature of Fahrenheit in terms of Celsius, it's 9/5 times the temperature in Celsius plus 32. And then we can plug in what we just figured out for converting from kelvin to Celsius and for the Celsius temperature here. So, we have temperature in kelvin minus 273.15 is a Celsius temperature written in kelvin. And then we can plug in and get our conversion to Fahrenheit. So, we have 0 degrees kelvin is absolute 0 minus 273.15 times 9/5 plus 32 gives negative 459.67 degrees Fahrenheit is what an absolute 0 is in Fahrenheit.

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