Giancoli's Physics: Principles with Applications, 7th Edition

13

Temperature and Kinetic Theory

Change chapter13-1: Atomic Theory

13-2: Temperature and Thermometers

13-4: Thermal Expansion

13-5: Gas Laws; Absolute Temperature

13-6 and 13-7: Ideal Gas Law

13-8: Ideal Gas Law in Terms of Molecules; Avogadro's Number

13-9: Molecular Interpretation of Temperature

13-11: Real Gases; Phase Changes

13-12: Vapor Pressure and Humidity

13-13: Diffusion

Question by Giancoli, Douglas C., Physics: Principles with Applications, 7th Ed., ©2014, Reprinted by permission of Pearson Education Inc., New York.

Problem 41

Q

A

300 \textrm{ molecules/cm}^3

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VIDEO TRANSCRIPT

This is Giancoli Answers with Mr. Dychko. *P V* equals the number of molecules times Boltzmann constant times temperature and we can solve this for *N* over *V* by dividing both sides by *V K* and *T*. So, we have pressure over *K T* because the *v's* cancel, equals the number of molecules divided by the volume and because the *K T* cancels here. And that's 10 to the minus 12 newtons per meter squared lowest attainable pressure, and then divided by Boltzmann constant 1.38 times 10 to the minus 23 joules per kelvin times the standard temperature of 273.15 kelvin. And this is going to give us number of molecules per cubic meter, and so we have to convert that into per cubic centimeter, because that's what the question asks us for, by multiplying by 1 meter for every 100 centimeters, cubed, and we end up with about 300 molecules per cubic centimeter.

COMMENTS

By bmalan on Wed, 7/29/2020 - 4:39 AM

Hello Mr. Dychko, I am not sure how but every time I plug this into my calculator I get 2,652 instead of 265.2.

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