Giancoli's Physics: Principles with Applications, 7th Edition

13

Temperature and Kinetic Theory

Change chapter13-1: Atomic Theory

13-2: Temperature and Thermometers

13-4: Thermal Expansion

13-5: Gas Laws; Absolute Temperature

13-6 and 13-7: Ideal Gas Law

13-8: Ideal Gas Law in Terms of Molecules; Avogadro's Number

13-9: Molecular Interpretation of Temperature

13-11: Real Gases; Phase Changes

13-12: Vapor Pressure and Humidity

13-13: Diffusion

Question by Giancoli, Douglas C., Physics: Principles with Applications, 7th Ed., ©2014, Reprinted by permission of Pearson Education Inc., New York.

Problem 3

Q

- “Room temperature” is often taken to be $68 ^\circ \textrm{F}$. What is this on the Celsius scale?
- The temperature of the filament in a lightbulb is about $1900 ^\circ \textrm{C}$. What is this on the Fahrenheit scale?

A

$20^\circ\textrm{C, } 3500^\circ\textrm{F}$

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VIDEO TRANSCRIPT

This is Giancoli Answers with Mr. Dychko. The temperature in degrees Celsius is 5/9 times the Fahrenheit temperature after you take away 32. So, 68 degrees Fahrenheit for room temperature minus 32 multiplied by 5/9 is 20 degrees Celsius. And then for the temperature inside a light bulb you take, the Fahrenheit temperature is calculated by going 5, or 9 over 5 times the temperature in Celsius and then add 32 after you do the multiplying. So, we have 9/5 times 1,900 degrees Celsius temperature of the filament plus 32. And that gives about 3,500 degrees Fahrenheit.

COMMENTS

By ljn8 on Mon, 11/17/2014 - 10:56 PM

This should be degrees F for part b

By Mr. Dychko on Mon, 11/17/2014 - 11:08 PM

Thanks a lot for noticing that ljn8, I've updated the text.

Cheers,

Mr. Dychko

By shine07 on Tue, 12/8/2015 - 3:26 AM

Can you please include the formulas first rather than just plugging in the numbers?

By shine07 on Tue, 12/8/2015 - 3:33 AM

Never mind. I read the question wrong.

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